First Things First

I'll get the screenshots out of the way first!

Warmup I

String I

List I

Logic I

What I found Interesting

Logic I: near_ten

This was the very last problem of the whole assignment, and it definitely stood out to me. I was able to write the python code that partially answered the assignment by using the following:

def near_ten(num):
  return (num%10<=2)

While this bit of code worked for numbers which were 2 or less OVER a multiple of 10, it did NOT work those that were two or less UNDER a multiple of 10 (i.e., it returned True for a number such as 42, but returned False for a number such as 39, which should still have returned True.) So, what to do about this? I pulled out a piece of paper and wrote a sequence of numbers, then came up with different rules I could write and tested them out to see if they worked logically. At first I thought I would need to use the abs() method, or several different modulus functions. However, I finally realized a much simpler way to do things- A simple or statement which would keep the same basic form, but merely shift the given number itself. My end code looked like:

def near_ten(num):
  return ((num%10<=2)) or ((num+2)%10<=2)

Woohoo!

Logic I: caught_speeding

I enjoyed this one mostly because I thought it was amusing, plus I had to figure out a way for the code to check for several paramters on two different variables. While it would have been just as correct to write out a set of rules for is_birthday == True and for is_birthday == False, I wanted to think of a way which was shorter and more concise. In the end, I realized I could define another variable which would be 0 when it was is_birthday == False, and would be 5 when is_birthday == True so that I could just add it on to one set of rules and another bit of logic would determine whether the variable should be 0 or 5. My code ended up being:

def caught_speeding(speed, is_birthday):
  excuse = 0
  if is_birthday:
    excuse = 5
  if speed<=60+excuse:
        return 0
  elif (speed>=61+excuse) and (speed<=80+excuse):
        return 1
  else:
        return 2

Don't speed, even if it is your birthday!

Logic I: cigar_party

Truthfully, I just enjoyed this one because the thought of squirrels smoking cigars at a party was so silly it made me laugh. Writing the python for it was pretty simple, as it only required a simple if/else statement (There is very likely a more concise way, but I'm not sure).

My code was:

def cigar_party(cigars, is_weekend):
    if is_weekend:
        return cigars>=40
    else:
        return (cigars>=40) and (cigars<=60) 

Tadah! Anyways, I kept thinking of this: