Post by Chunxi Zhang
Chunxi's CodingBat
Choose three exercise.
1.List1-make pi
I feel this one is very interesting is because the code is quiet simple. I thought the problem would be harder. So I tried to define pi as the first step. In fact, you do not need to do that. Finally, I simply type
return [3,1,4]
2.Logic-1 > date_fashion
I made a mistake at first. The logic here is interesting. The original version is:
def date_fashion(you, date):
if you>=8 or date>=8:
return 2
if you<=2 or date<=2:
return 0
else:
return 1
But is had problems. If you is greater than 8, your date is less than 2. It will return 2. What I expect is 0. Therefore, I changed the order.
def date_fashion(you, date):
if you<=2 or date<=2:
return 0
if you>=8 or date>=8:
return 2
else:
return 1
3.Logic-1 > caught_speeding
At the very beginning, I tried to devide into two parts. If it is my birthday or not. Then consider the speed. But I found out there were a lot to input. Most of them were same.Therefore, I tried to simpify the code. To make the code shorter. I define "boon", if it is not the birthday, it will be 0.
def caught_speeding(speed, is_birthday):
boon = 0
if is_birthday == True:
boon = 5
if speed <= 60+boon:
return 0
elif speed >= 81+boon:
return 2
else:
return 1
Pictures
warmup1
string1
list1
logic1
